Respuesta :

dalendrk
[tex]\lim\limits_{x\to0}\dfrac{\tan4x}{\tan3x}\stackrel{[H]}=\lim\limits_{x\to0}\left[\left(\dfrac{1}{\cos^24x}\cdot4\right):\left(\dfrac{1}{\cos^23x}\cdot3\right)\right]\\\\=\lim\limits_{x\to0}\left(\dfrac{4}{\cos^24x}\cdot\dfrac{\cos^23x}{3}\right)=\dfrac{4}{1}\cdot\dfrac{1}{3}=\dfrac{4}{3}\\------------------\\(\tan x)'=\dfrac{1}{\cos^2x}\\\\\lim\limits_{x\to0}\cos x=\cos0=1[/tex]

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