stewiegamerhd101 stewiegamerhd101
  • 03-08-2020
  • Mathematics
contestada

Solve: [tex]cos^2(2x)-sin^2(2x)=0[/tex] Thanks

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 03-08-2020

Answer:

x = pi/8   + pi/2  *n                    x = 3pi/8   +   pi /2 *n

Step-by-step explanation:

cos ^2 ( 2x) - sin ^2 (2x) = 0

Substitute u = 2x

cos ^2 ( u) - sin ^2 (u) = 0

We know cos ^2(x)-sin ^2(x)=cos (2x)

cos ( 2u) =0

Replacing u with 2x

cos  (2 *2x) =0

cos (4x) =0

cos u =0 when u = pi/2 + 2 pi n and 3pi/2 + 2 pi n  where n is an integer

4x = pi/2+2 pi n                    4x = 3pi/2+2pi n

x = pi/8   + pi/2  *n                    x = 3pi/8   +   pi /2 *n

Answer Link

Otras preguntas

or write an essay on "Together everyone achieves much​
Given the following table with selected values of the functions f (x) and g(x), determine f (g(2)) − g(f (−1)).x −5 −4 −1 2 4 7f (x) 11 9 −1 −3 −7 −13g(x) −10 −
For this equation, tell which method you used to solve it. x^2 + 2x = 7
5x = 80 X = my question is how to u get it and the answer ​
(a-2)^2=64 Please help solve?
Chris owes $920 on his credit card, which has a credit limit of $1800. He also has a debit card linked to a checking account with an available balance of $990.
please answer this and ill make u brainliest
Solve system by using the substitution method. y=2x+9 8x-3=y ( ? , )
How do you find the equation of a perpendicular bisect or of a line segment?
Why did the Republicans need the Democrats' help to put Rutherford B. Hayes into the Presidency?