kileyfullen kileyfullen

01-09-2020
Mathematics

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What is the inverse of g(x)= 1/x-1 and is it a function? 1/x Yes 1/x +1 Yes 1/x - 1 No 1/y-1 No

Respuesta :

Alfpfeu Alfpfeu

01-09-2020

Answer:

Step-by-step explanation:

hello,

[tex]g(x)=\dfrac{1}{x-1}\\\\x=g(g^{-1}(x))=\dfrac{1}{g^{-1}(x)-1} \\ \\g^{-1}(x)-1=\dfrac{1}{x}\\ \\g^{-1}(x)=\dfrac{1}{x}+1=\dfrac{1+x}{x}[/tex]

And this is a function defined for x different from 0.

Thanks

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