The function f is given by f(x)=3x^2+1. What is the average value of f over the closed interval [1,3]?

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02-11-2016
Mathematics

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The function f is given by f(x)=3x^2+1. What is the average value of f over the closed interval [1,3]?

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paran01dandr01d paran01dandr01d · Answer 1 · 2016-11-06T00:06:16+01:00

paran01dandr01d paran01dandr01d

06-11-2016

You can find the answer using the equation (f(b)-f(a))/(b-a). For this problem, a=1 and b=3.

Then, plug in the numbers and solve:
[(3(3)^2+1)-(3(1)^2+1)]/(3-1)
=(28-4)/2
=12

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